Let's take the limit x→∞lim(10x) Let's divide numerator and denominator by x: x→∞lim(10x) = x→∞lim10x11 Do Replacement u=x1 then x→∞lim10x11=u→0+lim(10u1) = 0⋅101=∞
The final answer: x→∞lim(10x)=∞
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type