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Limit of the function
:
Limit of (e^(4*x)-e^(3*x))/(-sin(3*x)+sin(4*x))
Limit of (-6-x^2-3*x+4*x^3)/(3-x^2+2*x^3)
Limit of ((3-x)^4-(2-x)^4)/((1-x)^4-(1+x)^4)
Limit of (-10+x^2+3*x)/(16+x^2-10*x)
Derivative of
:
2*e^(2*x)
Integral of d{x}
:
2*e^(2*x)
Graphing y =
:
2*e^(2*x)
Identical expressions
two *e^(two *x)
2 multiply by e to the power of (2 multiply by x)
two multiply by e to the power of (two multiply by x)
2*e(2*x)
2*e2*x
2e^(2x)
2e(2x)
2e2x
2e^2x
Limit of the function
/
2*e^(2*x)
Limit of the function 2*e^(2*x)
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/ 2*x\ lim \2*E / x->oo
lim
x
→
∞
(
2
e
2
x
)
\lim_{x \to \infty}\left(2 e^{2 x}\right)
x
→
∞
lim
(
2
e
2
x
)
Limit(2*E^(2*x), x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
0
2
4
6
8
-8
-6
-4
-2
-10
10
0
1000000000
Plot the graph
Rapid solution
[src]
oo
∞
\infty
∞
Expand and simplify
Other limits x→0, -oo, +oo, 1
lim
x
→
∞
(
2
e
2
x
)
=
∞
\lim_{x \to \infty}\left(2 e^{2 x}\right) = \infty
x
→
∞
lim
(
2
e
2
x
)
=
∞
lim
x
→
0
−
(
2
e
2
x
)
=
2
\lim_{x \to 0^-}\left(2 e^{2 x}\right) = 2
x
→
0
−
lim
(
2
e
2
x
)
=
2
More at x→0 from the left
lim
x
→
0
+
(
2
e
2
x
)
=
2
\lim_{x \to 0^+}\left(2 e^{2 x}\right) = 2
x
→
0
+
lim
(
2
e
2
x
)
=
2
More at x→0 from the right
lim
x
→
1
−
(
2
e
2
x
)
=
2
e
2
\lim_{x \to 1^-}\left(2 e^{2 x}\right) = 2 e^{2}
x
→
1
−
lim
(
2
e
2
x
)
=
2
e
2
More at x→1 from the left
lim
x
→
1
+
(
2
e
2
x
)
=
2
e
2
\lim_{x \to 1^+}\left(2 e^{2 x}\right) = 2 e^{2}
x
→
1
+
lim
(
2
e
2
x
)
=
2
e
2
More at x→1 from the right
lim
x
→
−
∞
(
2
e
2
x
)
=
0
\lim_{x \to -\infty}\left(2 e^{2 x}\right) = 0
x
→
−
∞
lim
(
2
e
2
x
)
=
0
More at x→-oo
The graph