$$\lim_{x \to \infty}\left(\sin{\left(x \right)} 2 \cos{\left(x \right)}\right) = \left\langle -2, 2\right\rangle$$
$$\lim_{x \to 0^-}\left(\sin{\left(x \right)} 2 \cos{\left(x \right)}\right) = 0$$
More at x→0 from the left$$\lim_{x \to 0^+}\left(\sin{\left(x \right)} 2 \cos{\left(x \right)}\right) = 0$$
More at x→0 from the right$$\lim_{x \to 1^-}\left(\sin{\left(x \right)} 2 \cos{\left(x \right)}\right) = 2 \sin{\left(1 \right)} \cos{\left(1 \right)}$$
More at x→1 from the left$$\lim_{x \to 1^+}\left(\sin{\left(x \right)} 2 \cos{\left(x \right)}\right) = 2 \sin{\left(1 \right)} \cos{\left(1 \right)}$$
More at x→1 from the right$$\lim_{x \to -\infty}\left(\sin{\left(x \right)} 2 \cos{\left(x \right)}\right) = \left\langle -2, 2\right\rangle$$
More at x→-oo