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Limit of the function
:
Limit of log(x)*tan(x)
Limit of tan(5*x)
Limit of sin(x/3)
Limit of 2*x/(1+x^2)
Derivative of
:
2/x^2
Graphing y =
:
2/x^2
Integral of d{x}
:
2/x^2
Identical expressions
two /x^ two
2 divide by x squared
two divide by x to the power of two
2/x2
2/x²
2/x to the power of 2
2 divide by x^2
Similar expressions
tan(x/2)^2/x^2
tan(3*x)^2/x^2
log(1-x^2)/x^2
(1+x+x^2)/(x^2-6*x)
Limit of the function
/
2/x^2
Limit of the function 2/x^2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
/2 \ lim |--| x->oo| 2| \x /
$$\lim_{x \to \infty}\left(\frac{2}{x^{2}}\right)$$
Limit(2/x^2, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(\frac{2}{x^{2}}\right)$$
Let's divide numerator and denominator by x^2:
$$\lim_{x \to \infty}\left(\frac{2}{x^{2}}\right)$$ =
$$\lim_{x \to \infty}\left(\frac{2 \frac{1}{x^{2}}}{1}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{2 \frac{1}{x^{2}}}{1}\right) = \lim_{u \to 0^+}\left(2 u^{2}\right)$$
=
$$2 \cdot 0^{2} = 0$$
The final answer:
$$\lim_{x \to \infty}\left(\frac{2}{x^{2}}\right) = 0$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
0
$$0$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(\frac{2}{x^{2}}\right) = 0$$
$$\lim_{x \to 0^-}\left(\frac{2}{x^{2}}\right) = \infty$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{2}{x^{2}}\right) = \infty$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(\frac{2}{x^{2}}\right) = 2$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{2}{x^{2}}\right) = 2$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{2}{x^{2}}\right) = 0$$
More at x→-oo
The graph