We have indeterminateness of type
0/0,
i.e. limit for the numerator is
x→0+limtan(8x)=0and limit for the denominator is
x→0+limsin(5x)=0Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→0+lim(sin(5x)tan(8x))=
x→0+lim(dxdsin(5x)dxdtan(8x))=
x→0+lim(5cos(5x)8tan2(8x)+8)=
x→0+lim(58tan2(8x)+58)=
x→0+lim(58tan2(8x)+58)=
58It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)