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Limit of the function
:
Limit of (1+3*x)^(5/x)
Limit of (-16+x^2+6*x)/(-2-5*x+3*x^2)
Limit of (1+x)^(2/3)-(-1+x)^(2/3)
Limit of 1/3+x/3
Graphing y =
:
t^2
Derivative of
:
t^2
Integral of d{x}
:
t^2
Identical expressions
t^ two
t squared
t to the power of two
t2
t²
t to the power of 2
Limit of the function
/
t^2
Limit of the function t^2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
2 lim t t->0+
$$\lim_{t \to 0^+} t^{2}$$
Limit(t^2, t, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
0
$$0$$
Expand and simplify
One‐sided limits
[src]
2 lim t t->0+
$$\lim_{t \to 0^+} t^{2}$$
0
$$0$$
= -9.68305799950874e-32
2 lim t t->0-
$$\lim_{t \to 0^-} t^{2}$$
0
$$0$$
= -9.68305799950874e-32
= -9.68305799950874e-32
Other limits t→0, -oo, +oo, 1
$$\lim_{t \to 0^-} t^{2} = 0$$
More at t→0 from the left
$$\lim_{t \to 0^+} t^{2} = 0$$
$$\lim_{t \to \infty} t^{2} = \infty$$
More at t→oo
$$\lim_{t \to 1^-} t^{2} = 1$$
More at t→1 from the left
$$\lim_{t \to 1^+} t^{2} = 1$$
More at t→1 from the right
$$\lim_{t \to -\infty} t^{2} = \infty$$
More at t→-oo
Numerical answer
[src]
-9.68305799950874e-32
-9.68305799950874e-32
The graph