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Limit of the function
:
Limit of 1/(-1+2*n)
Limit of (1+x)^3+(-1+x)^2-(-1+x)^3/(1+x)^2
Limit of tan(5*x)/tan(4*x)
Limit of sqrt((1+x)/x)
Graphing y =
:
sqrt((1+x)/x)
Identical expressions
sqrt((one +x)/x)
square root of ((1 plus x) divide by x)
square root of ((one plus x) divide by x)
√((1+x)/x)
sqrt1+x/x
sqrt((1+x) divide by x)
Similar expressions
((1+x)^(1/3)-sqrt(1+x))/x
-1/x+sqrt(1+x)/x
sqrt((1-x)/x)
sqrt(1+x)/x-sqrt(1-x)/x
(-6+6*sqrt(1+x))/x
Limit of the function
/
sqrt((1+x)/x)
Limit of the function sqrt((1+x)/x)
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
_______ / 1 + x lim / ----- x->oo\/ x
$$\lim_{x \to \infty} \sqrt{\frac{x + 1}{x}}$$
Limit(sqrt((1 + x)/x), x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
1
$$1$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty} \sqrt{\frac{x + 1}{x}} = 1$$
$$\lim_{x \to 0^-} \sqrt{\frac{x + 1}{x}} = \infty i$$
More at x→0 from the left
$$\lim_{x \to 0^+} \sqrt{\frac{x + 1}{x}} = \infty$$
More at x→0 from the right
$$\lim_{x \to 1^-} \sqrt{\frac{x + 1}{x}} = \sqrt{2}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \sqrt{\frac{x + 1}{x}} = \sqrt{2}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \sqrt{\frac{x + 1}{x}} = 1$$
More at x→-oo
The graph