i.e. limit for the numerator is x→π+limsin(x)=0 and limit for the denominator is x→π+limtan(2x)1=0 Let's take derivatives of the numerator and denominator until we eliminate indeterninateness. x→π+lim(sin(x)tan(2x)) = x→π+limdxdtan(2x)1dxdsin(x) = x→π+lim−2tan2(2x)−21cos(x)tan2(2x) = x→π+lim−2tan2(2x)−21cos(x)tan2(2x) = 2 It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)