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sin(sin(x))/sin(x)

Limit of the function sin(sin(x))/sin(x)

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     /sin(sin(x))\
 lim |-----------|
x->0+\   sin(x)  /
limx0+(sin(sin(x))sin(x))\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)
Limit(sin(sin(x))/sin(x), x, 0)
Lopital's rule
We have indeterminateness of type
0/0,

i.e. limit for the numerator is
limx0+sin(sin(x))=0\lim_{x \to 0^+} \sin{\left(\sin{\left(x \right)} \right)} = 0
and limit for the denominator is
limx0+sin(x)=0\lim_{x \to 0^+} \sin{\left(x \right)} = 0
Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
limx0+(sin(sin(x))sin(x))\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)
=
limx0+(ddxsin(sin(x))ddxsin(x))\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \sin{\left(\sin{\left(x \right)} \right)}}{\frac{d}{d x} \sin{\left(x \right)}}\right)
=
limx0+cos(sin(x))\lim_{x \to 0^+} \cos{\left(\sin{\left(x \right)} \right)}
=
limx0+1cos(x)\lim_{x \to 0^+} \frac{1}{\cos{\left(x \right)}}
=
limx0+1cos(x)\lim_{x \to 0^+} \frac{1}{\cos{\left(x \right)}}
=
11
It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)
The graph
02468-8-6-4-2-10100.81.2
One‐sided limits [src]
     /sin(sin(x))\
 lim |-----------|
x->0+\   sin(x)  /
limx0+(sin(sin(x))sin(x))\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)
1
11
= 1.0
     /sin(sin(x))\
 lim |-----------|
x->0-\   sin(x)  /
limx0(sin(sin(x))sin(x))\lim_{x \to 0^-}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)
1
11
= 1.0
= 1.0
Rapid solution [src]
1
11
Other limits x→0, -oo, +oo, 1
limx0(sin(sin(x))sin(x))=1\lim_{x \to 0^-}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = 1
More at x→0 from the left
limx0+(sin(sin(x))sin(x))=1\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = 1
limx(sin(sin(x))sin(x))\lim_{x \to \infty}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)
More at x→oo
limx1(sin(sin(x))sin(x))=sin(sin(1))sin(1)\lim_{x \to 1^-}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = \frac{\sin{\left(\sin{\left(1 \right)} \right)}}{\sin{\left(1 \right)}}
More at x→1 from the left
limx1+(sin(sin(x))sin(x))=sin(sin(1))sin(1)\lim_{x \to 1^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = \frac{\sin{\left(\sin{\left(1 \right)} \right)}}{\sin{\left(1 \right)}}
More at x→1 from the right
limx(sin(sin(x))sin(x))\lim_{x \to -\infty}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)
More at x→-oo
Numerical answer [src]
1.0
1.0
The graph
Limit of the function sin(sin(x))/sin(x)