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sin(sin(x))/sin(x)

Limit of the function sin(sin(x))/sin(x)

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The solution

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     /sin(sin(x))\
 lim |-----------|
x->0+\   sin(x)  /
$$\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)$$
Limit(sin(sin(x))/sin(x), x, 0)
Lopital's rule
We have indeterminateness of type
0/0,

i.e. limit for the numerator is
$$\lim_{x \to 0^+} \sin{\left(\sin{\left(x \right)} \right)} = 0$$
and limit for the denominator is
$$\lim_{x \to 0^+} \sin{\left(x \right)} = 0$$
Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
$$\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \sin{\left(\sin{\left(x \right)} \right)}}{\frac{d}{d x} \sin{\left(x \right)}}\right)$$
=
$$\lim_{x \to 0^+} \cos{\left(\sin{\left(x \right)} \right)}$$
=
$$\lim_{x \to 0^+} \frac{1}{\cos{\left(x \right)}}$$
=
$$\lim_{x \to 0^+} \frac{1}{\cos{\left(x \right)}}$$
=
$$1$$
It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)
The graph
One‐sided limits [src]
     /sin(sin(x))\
 lim |-----------|
x->0+\   sin(x)  /
$$\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)$$
1
$$1$$
= 1.0
     /sin(sin(x))\
 lim |-----------|
x->0-\   sin(x)  /
$$\lim_{x \to 0^-}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)$$
1
$$1$$
= 1.0
= 1.0
Rapid solution [src]
1
$$1$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 0^-}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = 1$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = 1$$
$$\lim_{x \to \infty}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)$$
More at x→oo
$$\lim_{x \to 1^-}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = \frac{\sin{\left(\sin{\left(1 \right)} \right)}}{\sin{\left(1 \right)}}$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right) = \frac{\sin{\left(\sin{\left(1 \right)} \right)}}{\sin{\left(1 \right)}}$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{\sin{\left(\sin{\left(x \right)} \right)}}{\sin{\left(x \right)}}\right)$$
More at x→-oo
Numerical answer [src]
1.0
1.0
The graph
Limit of the function sin(sin(x))/sin(x)