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(7+n)/(5+n)

Limit of the function (7+n)/(5+n)

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     /7 + n\
 lim |-----|
n->oo\5 + n/
limn(n+7n+5)\lim_{n \to \infty}\left(\frac{n + 7}{n + 5}\right)
Limit((7 + n)/(5 + n), n, oo, dir='-')
Detail solution
Let's take the limit
limn(n+7n+5)\lim_{n \to \infty}\left(\frac{n + 7}{n + 5}\right)
Let's divide numerator and denominator by n:
limn(n+7n+5)\lim_{n \to \infty}\left(\frac{n + 7}{n + 5}\right) =
limn(1+7n1+5n)\lim_{n \to \infty}\left(\frac{1 + \frac{7}{n}}{1 + \frac{5}{n}}\right)
Do Replacement
u=1nu = \frac{1}{n}
then
limn(1+7n1+5n)=limu0+(7u+15u+1)\lim_{n \to \infty}\left(\frac{1 + \frac{7}{n}}{1 + \frac{5}{n}}\right) = \lim_{u \to 0^+}\left(\frac{7 u + 1}{5 u + 1}\right)
=
07+105+1=1\frac{0 \cdot 7 + 1}{0 \cdot 5 + 1} = 1

The final answer:
limn(n+7n+5)=1\lim_{n \to \infty}\left(\frac{n + 7}{n + 5}\right) = 1
Lopital's rule
We have indeterminateness of type
oo/oo,

i.e. limit for the numerator is
limn(n+7)=\lim_{n \to \infty}\left(n + 7\right) = \infty
and limit for the denominator is
limn(n+5)=\lim_{n \to \infty}\left(n + 5\right) = \infty
Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
limn(n+7n+5)\lim_{n \to \infty}\left(\frac{n + 7}{n + 5}\right)
=
limn(ddn(n+7)ddn(n+5))\lim_{n \to \infty}\left(\frac{\frac{d}{d n} \left(n + 7\right)}{\frac{d}{d n} \left(n + 5\right)}\right)
=
limn1\lim_{n \to \infty} 1
=
limn1\lim_{n \to \infty} 1
=
11
It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)
The graph
02468-8-6-4-2-1010-5050
Rapid solution [src]
1
11
Other limits n→0, -oo, +oo, 1
limn(n+7n+5)=1\lim_{n \to \infty}\left(\frac{n + 7}{n + 5}\right) = 1
limn0(n+7n+5)=75\lim_{n \to 0^-}\left(\frac{n + 7}{n + 5}\right) = \frac{7}{5}
More at n→0 from the left
limn0+(n+7n+5)=75\lim_{n \to 0^+}\left(\frac{n + 7}{n + 5}\right) = \frac{7}{5}
More at n→0 from the right
limn1(n+7n+5)=43\lim_{n \to 1^-}\left(\frac{n + 7}{n + 5}\right) = \frac{4}{3}
More at n→1 from the left
limn1+(n+7n+5)=43\lim_{n \to 1^+}\left(\frac{n + 7}{n + 5}\right) = \frac{4}{3}
More at n→1 from the right
limn(n+7n+5)=1\lim_{n \to -\infty}\left(\frac{n + 7}{n + 5}\right) = 1
More at n→-oo
The graph
Limit of the function (7+n)/(5+n)