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(1+1/n)^n

Limit of the function (1+1/n)^n

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             n
      /    1\ 
 lim  |1 + -| 
n->-oo\    n/ 
$$\lim_{n \to -\infty} \left(1 + \frac{1}{n}\right)^{n}$$
Limit((1 + 1/n)^n, n, -oo)
Detail solution
Let's take the limit
$$\lim_{n \to -\infty} \left(1 + \frac{1}{n}\right)^{n}$$
transform
do replacement
$$u = \frac{n}{1}$$
then
$$\lim_{n \to -\infty} \left(1 + \frac{1}{n}\right)^{n}$$ =
=
$$\lim_{u \to -\infty} \left(1 + \frac{1}{u}\right)^{u}$$
=
$$\lim_{u \to -\infty} \left(1 + \frac{1}{u}\right)^{u}$$
=
$$\left(\left(\lim_{u \to -\infty} \left(1 + \frac{1}{u}\right)^{u}\right)\right)$$
The limit
$$\lim_{u \to -\infty} \left(1 + \frac{1}{u}\right)^{u}$$
is second remarkable limit, is equal to e ~ 2.718281828459045
then
$$\left(\left(\lim_{u \to -\infty} \left(1 + \frac{1}{u}\right)^{u}\right)\right) = e$$

The final answer:
$$\lim_{n \to -\infty} \left(1 + \frac{1}{n}\right)^{n} = e$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
E
$$e$$
Other limits n→0, -oo, +oo, 1
$$\lim_{n \to -\infty} \left(1 + \frac{1}{n}\right)^{n} = e$$
$$\lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^{n} = e$$
More at n→oo
$$\lim_{n \to 0^-} \left(1 + \frac{1}{n}\right)^{n} = 1$$
More at n→0 from the left
$$\lim_{n \to 0^+} \left(1 + \frac{1}{n}\right)^{n} = 1$$
More at n→0 from the right
$$\lim_{n \to 1^-} \left(1 + \frac{1}{n}\right)^{n} = 2$$
More at n→1 from the left
$$\lim_{n \to 1^+} \left(1 + \frac{1}{n}\right)^{n} = 2$$
More at n→1 from the right
The graph
Limit of the function (1+1/n)^n