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1-3*x

Limit of the function 1-3*x

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The solution

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 lim (1 - 3*x)
x->oo         
$$\lim_{x \to \infty}\left(1 - 3 x\right)$$
Limit(1 - 3*x, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(1 - 3 x\right)$$
Let's divide numerator and denominator by x:
$$\lim_{x \to \infty}\left(1 - 3 x\right)$$ =
$$\lim_{x \to \infty}\left(\frac{-3 + \frac{1}{x}}{\frac{1}{x}}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{-3 + \frac{1}{x}}{\frac{1}{x}}\right) = \lim_{u \to 0^+}\left(\frac{u - 3}{u}\right)$$
=
$$\frac{-3}{0} = -\infty$$

The final answer:
$$\lim_{x \to \infty}\left(1 - 3 x\right) = -\infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
-oo
$$-\infty$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(1 - 3 x\right) = -\infty$$
$$\lim_{x \to 0^-}\left(1 - 3 x\right) = 1$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(1 - 3 x\right) = 1$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(1 - 3 x\right) = -2$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(1 - 3 x\right) = -2$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(1 - 3 x\right) = \infty$$
More at x→-oo
The graph
Limit of the function 1-3*x