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Limit of the function
:
Limit of (-1+x)/(x+x^2)
Limit of log(-5+x)/log(e^x-e^5)
Limit of (-exp(-x)-2*x+exp(x))/(x-sin(x))
Limit of (e^(4*x)-e^(3*x))/(-sin(3*x)+sin(4*x))
1-3*x
Identical expressions
one - three *x
1 minus 3 multiply by x
one minus three multiply by x
1-3x
Similar expressions
1+3*x
Limit of the function
/
1-3*x
Limit of the function 1-3*x
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
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[src]
lim (1 - 3*x) x->oo
$$\lim_{x \to \infty}\left(1 - 3 x\right)$$
Limit(1 - 3*x, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(1 - 3 x\right)$$
Let's divide numerator and denominator by x:
$$\lim_{x \to \infty}\left(1 - 3 x\right)$$ =
$$\lim_{x \to \infty}\left(\frac{-3 + \frac{1}{x}}{\frac{1}{x}}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{-3 + \frac{1}{x}}{\frac{1}{x}}\right) = \lim_{u \to 0^+}\left(\frac{u - 3}{u}\right)$$
=
$$\frac{-3}{0} = -\infty$$
The final answer:
$$\lim_{x \to \infty}\left(1 - 3 x\right) = -\infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
-oo
$$-\infty$$
Expand and simplify
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(1 - 3 x\right) = -\infty$$
$$\lim_{x \to 0^-}\left(1 - 3 x\right) = 1$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(1 - 3 x\right) = 1$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(1 - 3 x\right) = -2$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(1 - 3 x\right) = -2$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(1 - 3 x\right) = \infty$$
More at x→-oo
The graph