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Limit of the function
:
Limit of 7-2*x
Limit of (4+x^2-5*x)/(-16+x^2)
Limit of (2-7*x+3*x^2)/(2-5*x+2*x^2)
Limit of (-1+x)/(-1+x^3)
Integral of d{x}
:
1/8
Sum of series
:
1/8
Derivative of
:
1/8
Identical expressions
one / eight
1 divide by 8
one divide by eight
Similar expressions
1/(8+x)
1+(1/(8*x))^(-8+2*x)
Limit of the function
/
1/8
Limit of the function 1/8
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
lim (1/8) x->oo
lim
x
→
∞
1
8
\lim_{x \to \infty} \frac{1}{8}
x
→
∞
lim
8
1
Limit(1/8, x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
-0.010
-0.008
-0.006
-0.004
-0.002
0.010
0.000
0.002
0.004
0.006
0.008
0.00
Plot the graph
Other limits x→0, -oo, +oo, 1
lim
x
→
∞
1
8
=
1
8
\lim_{x \to \infty} \frac{1}{8} = \frac{1}{8}
x
→
∞
lim
8
1
=
8
1
lim
x
→
0
−
1
8
=
1
8
\lim_{x \to 0^-} \frac{1}{8} = \frac{1}{8}
x
→
0
−
lim
8
1
=
8
1
More at x→0 from the left
lim
x
→
0
+
1
8
=
1
8
\lim_{x \to 0^+} \frac{1}{8} = \frac{1}{8}
x
→
0
+
lim
8
1
=
8
1
More at x→0 from the right
lim
x
→
1
−
1
8
=
1
8
\lim_{x \to 1^-} \frac{1}{8} = \frac{1}{8}
x
→
1
−
lim
8
1
=
8
1
More at x→1 from the left
lim
x
→
1
+
1
8
=
1
8
\lim_{x \to 1^+} \frac{1}{8} = \frac{1}{8}
x
→
1
+
lim
8
1
=
8
1
More at x→1 from the right
lim
x
→
−
∞
1
8
=
1
8
\lim_{x \to -\infty} \frac{1}{8} = \frac{1}{8}
x
→
−
∞
lim
8
1
=
8
1
More at x→-oo
Rapid solution
[src]
1/8
1
8
\frac{1}{8}
8
1
Expand and simplify
The graph