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9-x^2

Limit of the function 9-x^2

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     /     2\
 lim \9 - x /
x->3+        
$$\lim_{x \to 3^+}\left(9 - x^{2}\right)$$
Limit(9 - x^2, x, 3)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
0
$$0$$
One‐sided limits [src]
     /     2\
 lim \9 - x /
x->3+        
$$\lim_{x \to 3^+}\left(9 - x^{2}\right)$$
0
$$0$$
= 4.5492224530916e-32
     /     2\
 lim \9 - x /
x->3-        
$$\lim_{x \to 3^-}\left(9 - x^{2}\right)$$
0
$$0$$
= 1.48168935459259e-31
= 1.48168935459259e-31
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 3^-}\left(9 - x^{2}\right) = 0$$
More at x→3 from the left
$$\lim_{x \to 3^+}\left(9 - x^{2}\right) = 0$$
$$\lim_{x \to \infty}\left(9 - x^{2}\right) = -\infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(9 - x^{2}\right) = 9$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(9 - x^{2}\right) = 9$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(9 - x^{2}\right) = 8$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(9 - x^{2}\right) = 8$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(9 - x^{2}\right) = -\infty$$
More at x→-oo
Numerical answer [src]
4.5492224530916e-32
4.5492224530916e-32
The graph
Limit of the function 9-x^2