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Limit of the function
:
Limit of x^2*(1/3-cos(8*x)/3)
Limit of (-2+x^2-x)/(-2+x+3*x^2)
Limit of (-1+sin(x))/cos(x)
Limit of (-2*sin(x)+sin(2*x))/(x*log(cos(5*x)))
Sum of series
:
9/2
Identical expressions
nine / two
9 divide by 2
nine divide by two
Limit of the function
/
9/2
Limit of the function 9/2
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
lim (9/2) x->0+
$$\lim_{x \to 0^+} \frac{9}{2}$$
Limit(9/2, x, 0)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
9/2
$$\frac{9}{2}$$
Expand and simplify
One‐sided limits
[src]
lim (9/2) x->0+
$$\lim_{x \to 0^+} \frac{9}{2}$$
9/2
$$\frac{9}{2}$$
= 4.5
lim (9/2) x->0-
$$\lim_{x \to 0^-} \frac{9}{2}$$
9/2
$$\frac{9}{2}$$
= 4.5
= 4.5
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 0^-} \frac{9}{2} = \frac{9}{2}$$
More at x→0 from the left
$$\lim_{x \to 0^+} \frac{9}{2} = \frac{9}{2}$$
$$\lim_{x \to \infty} \frac{9}{2} = \frac{9}{2}$$
More at x→oo
$$\lim_{x \to 1^-} \frac{9}{2} = \frac{9}{2}$$
More at x→1 from the left
$$\lim_{x \to 1^+} \frac{9}{2} = \frac{9}{2}$$
More at x→1 from the right
$$\lim_{x \to -\infty} \frac{9}{2} = \frac{9}{2}$$
More at x→-oo
Numerical answer
[src]
4.5
4.5
The graph