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Limit of the function
:
Limit of (-2*x^2+4*x^3+5*x)/(3*x^2+7*x)
Limit of (-cos(5*x)+cos(3*x))/x^2
Limit of (-1+cos(7*x))/(-1+cos(3*x))
Limit of (16+x^2+10*x)/(-6+x^2-x)
Sum of series
:
n^3
Graphing y =
:
n^3
Identical expressions
n^ three
n cubed
n to the power of three
n3
n³
n to the power of 3
Similar expressions
(-1+n^3)/(1+n^2)
e^(-n)*n^3
(1+n^2-3*n)/(n+n^3)
(4+3*n^2)/(1+n^2+n^3)
x^x/factorial(n)^3
Limit of the function
/
n^3
Limit of the function n^3
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
3 lim n n->oo
$$\lim_{n \to \infty} n^{3}$$
Limit(n^3, n, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{n \to \infty} n^{3}$$
Let's divide numerator and denominator by n^3:
$$\lim_{n \to \infty} n^{3}$$ =
$$\lim_{n \to \infty} \frac{1}{\frac{1}{n^{3}}}$$
Do Replacement
$$u = \frac{1}{n}$$
then
$$\lim_{n \to \infty} \frac{1}{\frac{1}{n^{3}}} = \lim_{u \to 0^+} \frac{1}{u^{3}}$$
=
$$\frac{1}{0} = \infty$$
The final answer:
$$\lim_{n \to \infty} n^{3} = \infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Rapid solution
[src]
oo
$$\infty$$
Expand and simplify
Other limits n→0, -oo, +oo, 1
$$\lim_{n \to \infty} n^{3} = \infty$$
$$\lim_{n \to 0^-} n^{3} = 0$$
More at n→0 from the left
$$\lim_{n \to 0^+} n^{3} = 0$$
More at n→0 from the right
$$\lim_{n \to 1^-} n^{3} = 1$$
More at n→1 from the left
$$\lim_{n \to 1^+} n^{3} = 1$$
More at n→1 from the right
$$\lim_{n \to -\infty} n^{3} = -\infty$$
More at n→-oo
The graph