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-x^2

Limit of the function -x^2

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     /  2\
 lim \-x /
x->oo     
$$\lim_{x \to \infty}\left(- x^{2}\right)$$
Limit(-x^2, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(- x^{2}\right)$$
Let's divide numerator and denominator by x^2:
$$\lim_{x \to \infty}\left(- x^{2}\right)$$ =
$$\lim_{x \to \infty} \frac{1}{\left(-1\right) \frac{1}{x^{2}}}$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty} \frac{1}{\left(-1\right) \frac{1}{x^{2}}} = \lim_{u \to 0^+}\left(- \frac{1}{u^{2}}\right)$$
=
$$- \frac{1}{0} = -\infty$$

The final answer:
$$\lim_{x \to \infty}\left(- x^{2}\right) = -\infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
-oo
$$-\infty$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(- x^{2}\right) = -\infty$$
$$\lim_{x \to 0^-}\left(- x^{2}\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(- x^{2}\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(- x^{2}\right) = -1$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(- x^{2}\right) = -1$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(- x^{2}\right) = -\infty$$
More at x→-oo
The graph
Limit of the function -x^2