We have indeterminateness of type
oo/oo,
i.e. limit for the numerator is
x→∞limlog(x)3=∞and limit for the denominator is
x→∞limx=∞Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→∞lim(xlog(x)3)=
x→∞lim(dxdxdxdlog(x)3)=
x→∞lim(x3log(x)2)=
x→∞lim(dxd3xdxdlog(x)2)=
x→∞lim(x6log(x))=
x→∞lim(x6log(x))=
0It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 2 time(s)