We have indeterminateness of type
0/0,
i.e. limit for the numerator is
x→0+limlog(1−x2)=0and limit for the denominator is
x→0+limx2=0Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→0+lim(x2log(1−x2))=
Let's transform the function under the limit a few
x→0+lim(x2log(1−x2))=
x→0+lim(dxdx2dxdlog(1−x2))=
x→0+lim(−1−x21)=
x→0+lim−1=
x→0+lim(dxd2xdxd(−2x))=
x→0+lim−1=
x→0+lim−1=
−1It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 2 time(s)