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5/x^3

Limit of the function 5/x^3

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     /5 \
 lim |--|
x->oo| 3|
     \x /
$$\lim_{x \to \infty}\left(\frac{5}{x^{3}}\right)$$
Limit(5/x^3, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(\frac{5}{x^{3}}\right)$$
Let's divide numerator and denominator by x^3:
$$\lim_{x \to \infty}\left(\frac{5}{x^{3}}\right)$$ =
$$\lim_{x \to \infty}\left(\frac{5 \frac{1}{x^{3}}}{1}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{5 \frac{1}{x^{3}}}{1}\right) = \lim_{u \to 0^+}\left(5 u^{3}\right)$$
=
$$5 \cdot 0^{3} = 0$$

The final answer:
$$\lim_{x \to \infty}\left(\frac{5}{x^{3}}\right) = 0$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(\frac{5}{x^{3}}\right) = 0$$
$$\lim_{x \to 0^-}\left(\frac{5}{x^{3}}\right) = -\infty$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(\frac{5}{x^{3}}\right) = \infty$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(\frac{5}{x^{3}}\right) = 5$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(\frac{5}{x^{3}}\right) = 5$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(\frac{5}{x^{3}}\right) = 0$$
More at x→-oo
Rapid solution [src]
0
$$0$$
The graph
Limit of the function 5/x^3