We have indeterminateness of type
oo/oo,
i.e. limit for the numerator is
x→∞limx!=∞and limit for the denominator is
x→∞limx2=∞Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→∞lim(x2x!)=
Let's transform the function under the limit a few
x→∞lim(x2x!)=
x→∞lim(dxdx2dxdx!)=
x→∞lim(2xΓ(x+1)polygamma(0,x+1))=
x→∞lim(dxd2xdxdΓ(x+1)polygamma(0,x+1))=
x→∞lim(2Γ(x+1)polygamma2(0,x+1)+2Γ(x+1)polygamma(1,x+1))=
x→∞lim(2Γ(x+1)polygamma2(0,x+1)+2Γ(x+1)polygamma(1,x+1))=
∞It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 2 time(s)