We have indeterminateness of type
oo/oo,
i.e. limit for the numerator is
x→∞limlog(x)=∞and limit for the denominator is
x→∞limex=∞Let's take derivatives of the numerator and denominator until we eliminate indeterninateness.
x→∞lim(e−xlog(x))=
x→∞lim(dxdexdxdlog(x))=
x→∞lim(xe−x)=
x→∞lim(xe−x)=
0It can be seen that we have applied Lopital's rule (we have taken derivatives with respect to the numerator and denominator) 1 time(s)