Mister Exam

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8+x

Limit of the function 8+x

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 lim (8 + x)
x->3+       
$$\lim_{x \to 3^+}\left(x + 8\right)$$
Limit(8 + x, x, 3)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
11
$$11$$
One‐sided limits [src]
 lim (8 + x)
x->3+       
$$\lim_{x \to 3^+}\left(x + 8\right)$$
11
$$11$$
= 11.0
 lim (8 + x)
x->3-       
$$\lim_{x \to 3^-}\left(x + 8\right)$$
11
$$11$$
= 11.0
= 11.0
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 3^-}\left(x + 8\right) = 11$$
More at x→3 from the left
$$\lim_{x \to 3^+}\left(x + 8\right) = 11$$
$$\lim_{x \to \infty}\left(x + 8\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(x + 8\right) = 8$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(x + 8\right) = 8$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(x + 8\right) = 9$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(x + 8\right) = 9$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(x + 8\right) = -\infty$$
More at x→-oo
Numerical answer [src]
11.0
11.0
The graph
Limit of the function 8+x