1 / | | (8 + x) dx | / 0
Integral(8 + x, (x, 0, 1))
Integrate term-by-term:
The integral of is when :
The integral of a constant is the constant times the variable of integration:
The result is:
Now simplify:
Add the constant of integration:
The answer is:
/ 2 | x | (8 + x) dx = C + -- + 8*x | 2 /
Use the examples entering the upper and lower limits of integration.