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e^(2*x)
Limit of the function/ e^(2*x)

Limit of the function e^(2*x)

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The solution

You have entered [src] 
      2*x
 lim E   
x->1+
lim⁡x→1+e2x\lim_{x \to 1^+} e^{2 x} 
Limit(E^(2*x), x, 1)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
-2.0-1.5-1.0-0.52.00.00.51.01.50100
Plot the graph
One‐sided limits [src] 
      2*x
 lim E   
x->1+
lim⁡x→1+e2x\lim_{x \to 1^+} e^{2 x} 
 2
e
e2e^{2} 
= 7.38905609893065
      2*x
 lim E   
x->1-
lim⁡x→1−e2x\lim_{x \to 1^-} e^{2 x} 
 2
e
e2e^{2} 
= 7.38905609893065
= 7.38905609893065
Rapid solution [src] 
 2
e
e2e^{2}
Expand and simplify
Other limits x→0, -oo, +oo, 1
lim⁡x→1−e2x=e2\lim_{x \to 1^-} e^{2 x} = e^{2}
More at x→1 from the left
lim⁡x→1+e2x=e2\lim_{x \to 1^+} e^{2 x} = e^{2}
lim⁡x→∞e2x=∞\lim_{x \to \infty} e^{2 x} = \infty
More at x→oo
lim⁡x→0−e2x=1\lim_{x \to 0^-} e^{2 x} = 1
More at x→0 from the left
lim⁡x→0+e2x=1\lim_{x \to 0^+} e^{2 x} = 1
More at x→0 from the right
lim⁡x→−∞e2x=0\lim_{x \to -\infty} e^{2 x} = 0
More at x→-oo
Numerical answer [src] 
7.38905609893065
7.38905609893065
The graph
Limit of the function e^(2*x)
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