Integral of ye^x dx

1. The integral of a constant times a function is the constant times the integral of the function:

   $$\int e^{x} y\, dx = y \int e^{x}\, dx$$

   1. The integral of the exponential function is itself.

      $$\int e^{x}\, dx = e^{x}$$

   So, the result is: $y e^{x}$

2. Add the constant of integration:

   $$y e^{x}+ \mathrm{constant}$$

The answer is:

$$y e^{x}+ \mathrm{constant}$$