Integral of xe^xcos(8x) dx
The solution
Detail solution
-
Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=x and let dv(x)=excos(8x).
Then du(x)=1.
To find v(x):
-
Use integration by parts, noting that the integrand eventually repeats itself.
-
For the integrand excos(8x):
Let u(x)=cos(8x) and let dv(x)=ex.
Then ∫excos(8x)dx=excos(8x)−∫(−8exsin(8x))dx.
-
For the integrand −8exsin(8x):
Let u(x)=−8sin(8x) and let dv(x)=ex.
Then ∫excos(8x)dx=8exsin(8x)+excos(8x)+∫(−64excos(8x))dx.
-
Notice that the integrand has repeated itself, so move it to one side:
65∫excos(8x)dx=8exsin(8x)+excos(8x)
Therefore,
∫excos(8x)dx=658exsin(8x)+65excos(8x)
Now evaluate the sub-integral.
-
Integrate term-by-term:
-
The integral of a constant times a function is the constant times the integral of the function:
∫658exsin(8x)dx=658∫exsin(8x)dx
-
Use integration by parts, noting that the integrand eventually repeats itself.
-
For the integrand exsin(8x):
Let u(x)=sin(8x) and let dv(x)=ex.
Then ∫exsin(8x)dx=exsin(8x)−∫8excos(8x)dx.
-
For the integrand 8excos(8x):
Let u(x)=8cos(8x) and let dv(x)=ex.
Then ∫exsin(8x)dx=exsin(8x)−8excos(8x)+∫(−64exsin(8x))dx.
-
Notice that the integrand has repeated itself, so move it to one side:
65∫exsin(8x)dx=exsin(8x)−8excos(8x)
Therefore,
∫exsin(8x)dx=65exsin(8x)−658excos(8x)
So, the result is: 42258exsin(8x)−422564excos(8x)
-
The integral of a constant times a function is the constant times the integral of the function:
∫65excos(8x)dx=65∫excos(8x)dx
-
Use integration by parts, noting that the integrand eventually repeats itself.
-
For the integrand excos(8x):
Let u(x)=cos(8x) and let dv(x)=ex.
Then ∫excos(8x)dx=excos(8x)−∫(−8exsin(8x))dx.
-
For the integrand −8exsin(8x):
Let u(x)=−8sin(8x) and let dv(x)=ex.
Then ∫excos(8x)dx=8exsin(8x)+excos(8x)+∫(−64excos(8x))dx.
-
Notice that the integrand has repeated itself, so move it to one side:
65∫excos(8x)dx=8exsin(8x)+excos(8x)
Therefore,
∫excos(8x)dx=658exsin(8x)+65excos(8x)
So, the result is: 42258exsin(8x)+4225excos(8x)
The result is: 422516exsin(8x)−422563excos(8x)
-
Now simplify:
4225(65x(8sin(8x)+cos(8x))−16sin(8x)+63cos(8x))ex
-
Add the constant of integration:
4225(65x(8sin(8x)+cos(8x))−16sin(8x)+63cos(8x))ex+constant
The answer is:
4225(65x(8sin(8x)+cos(8x))−16sin(8x)+63cos(8x))ex+constant
The answer (Indefinite)
[src]
/
| / x x \ x x
| x |cos(8*x)*e 8*e *sin(8*x)| 16*e *sin(8*x) 63*cos(8*x)*e
| x*E *cos(8*x) dx = C + x*|----------- + -------------| - -------------- + --------------
| \ 65 65 / 4225 4225
/
∫exxcos(8x)dx=C+x(658exsin(8x)+65excos(8x))−422516exsin(8x)+422563excos(8x)
The graph
63 128*E*cos(8) 504*E*sin(8)
- ---- + ------------ + ------------
4225 4225 4225
−422563+4225128ecos(8)+4225504esin(8)
=
63 128*E*cos(8) 504*E*sin(8)
- ---- + ------------ + ------------
4225 4225 4225
−422563+4225128ecos(8)+4225504esin(8)
-63/4225 + 128*E*cos(8)/4225 + 504*E*sin(8)/4225
Use the examples entering the upper and lower limits of integration.