Integral of (x^2+1)^2 dx
The solution
Detail solution
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Rewrite the integrand:
(x2+1)2=x4+2x2+1
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫x4dx=5x5
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The integral of a constant times a function is the constant times the integral of the function:
∫2x2dx=2∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: 32x3
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 5x5+32x3+x
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Add the constant of integration:
5x5+32x3+x+constant
The answer is:
5x5+32x3+x+constant
The answer (Indefinite)
[src]
/
|
| 2 5 3
| / 2 \ x 2*x
| \x + 1/ dx = C + x + -- + ----
| 5 3
/
∫(x2+1)2dx=C+5x5+32x3+x
The graph
Use the examples entering the upper and lower limits of integration.