Integral of (x^2+log^2(x))/x dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Let u=log(x).
Then let du=xdx and substitute du:
∫(u2+e2u)du
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Integrate term-by-term:
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
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There are multiple ways to do this integral.
Method #1
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Let u=2u.
Then let du=2du and substitute 2du:
∫4eudu
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The integral of a constant times a function is the constant times the integral of the function:
∫2eudu=2∫eudu
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: 2eu
Now substitute u back in:
2e2u
Method #2
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Let u=e2u.
Then let du=2e2udu and substitute 2du:
∫41du
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The integral of a constant times a function is the constant times the integral of the function:
∫21du=2∫1du
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: 2u
Now substitute u back in:
2e2u
The result is: 3u3+2e2u
Now substitute u back in:
2x2+3log(x)3
Method #2
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Rewrite the integrand:
xx2+log(x)2=x+xlog(x)2
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
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Let u=x1.
Then let du=−x2dx and substitute −du:
∫ulog(u1)2du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−ulog(u1)2)du=−∫ulog(u1)2du
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Let u=log(u1).
Then let du=−udu and substitute −du:
∫u2du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−u2)du=−∫u2du
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: −3u3
Now substitute u back in:
−3log(u1)3
So, the result is: 3log(u1)3
Now substitute u back in:
3log(x)3
The result is: 2x2+3log(x)3
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Add the constant of integration:
2x2+3log(x)3+constant
The answer is:
2x2+3log(x)3+constant
The answer (Indefinite)
[src]
/
|
| 2 2 2 3
| x + log (x) x log (x)
| ------------ dx = C + -- + -------
| x 2 3
|
/
3(logx)3+2x2
Use the examples entering the upper and lower limits of integration.