Integral of x^2+2x-8 dx

1. Integrate term-by-term:

   1. Integrate term-by-term:

      1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

         $$\int x^{2}\, dx = \frac{x^{3}}{3}$$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 2 x\, dx = 2 \int x\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x\, dx = \frac{x^{2}}{2}$$

         So, the result is: $x^{2}$

      The result is: $\frac{x^{3}}{3} + x^{2}$

   1. The integral of a constant is the constant times the variable of integration:

      $$\int \left(-8\right)\, dx = - 8 x$$

   The result is: $\frac{x^{3}}{3} + x^{2} - 8 x$

2. Now simplify:

   $$\frac{x \left(x^{2} + 3 x - 24\right)}{3}$$

3. Add the constant of integration:

   $$\frac{x \left(x^{2} + 3 x - 24\right)}{3}+ \mathrm{constant}$$

The answer is: