Integral of (x^2-4)/x dx
The solution
Detail solution
-
There are multiple ways to do this integral.
Method #1
-
Let u=x2.
Then let du=2xdx and substitute 2du:
∫2uu−4du
-
The integral of a constant times a function is the constant times the integral of the function:
∫uu−4du=2∫uu−4du
-
Rewrite the integrand:
uu−4=1−u4
-
Integrate term-by-term:
-
The integral of a constant is the constant times the variable of integration:
∫1du=u
-
The integral of a constant times a function is the constant times the integral of the function:
∫(−u4)du=−4∫u1du
-
The integral of u1 is log(u).
So, the result is: −4log(u)
The result is: u−4log(u)
So, the result is: 2u−2log(u)
Now substitute u back in:
2x2−2log(x2)
Method #2
-
Rewrite the integrand:
xx2−4=x−x4
-
Integrate term-by-term:
-
The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
-
The integral of a constant times a function is the constant times the integral of the function:
∫(−x4)dx=−4∫x1dx
-
The integral of x1 is log(x).
So, the result is: −4log(x)
The result is: 2x2−4log(x)
-
Add the constant of integration:
2x2−2log(x2)+constant
The answer is:
2x2−2log(x2)+constant
The answer (Indefinite)
[src]
/
|
| 2 2
| x - 4 x / 2\
| ------ dx = C + -- - 2*log\x /
| x 2
|
/
∫xx2−4dx=C+2x2−2log(x2)
The graph
Use the examples entering the upper and lower limits of integration.