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- Improper integral
- Double Integral
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- Derivative Step by Step
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How to use it?
- Integral of d{x}:
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Integral of exp(7*x)*sin(x)
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Integral of sin(x)^2*cos(x)^4
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Integral of 1/(1+(x+1)^(1/3))
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Integral of x^2*lnx
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Identical expressions
- one /(one +(x+ one)^(one / three))
- 1 divide by (1 plus (x plus 1) to the power of (1 divide by 3))
- one divide by (one plus (x plus one) to the power of (one divide by three))
- 1/(1+(x+1)(1/3))
- 1/1+x+11/3
- 1/1+x+1^1/3
- 1 divide by (1+(x+1)^(1 divide by 3))
- 1/(1+(x+1)^(1/3))dx
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Similar expressions
- 1/(1+(x-1)^(1/3))
- 1/(1-(x+1)^(1/3))
Integral of 1/(1+(x+1)^(1/3)) dx
The solution
You have entered
[src]
1 / | | 1 | 1*------------- dx | 3 _______ | 1 + \/ x + 1 | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{\sqrt[3]{x + 1} + 1}\, dx$$
Integral(1/(1 + (x + 1)^(1/3)), (x, 0, 1))
The answer (Indefinite)
[src]
/ | 2/3 | 1 3 _______ / 3 _______\ 3*(1 + x) | 1*------------- dx = C - 3*\/ 1 + x + 3*log\1 + \/ 1 + x / + ------------ | 3 _______ 2 | 1 + \/ x + 1 | /
$$3\,\left(\log \left(\left(x+1\right)^{{{1}\over{3}}}+1\right)+{{
\left(x+1\right)^{{{2}\over{3}}}-2\,\left(x+1\right)^{{{1}\over{3}}}
}\over{2}}\right)$$
The graph
The answer
[src]
2/3 3 3 ___ / 3 ___\ 3*2 - - 3*\/ 2 - 3*log(2) + 3*log\1 + \/ 2 / + ------ 2 2
$$3\,\log \left(2^{{{1}\over{3}}}+1\right)-3\,\log 2-3\,2^{{{1}\over{
3}}}+{{3}\over{2^{{{1}\over{3}}}}}+{{3}\over{2}}$$
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2/3 3 3 ___ / 3 ___\ 3*2 - - 3*\/ 2 - 3*log(2) + 3*log\1 + \/ 2 / + ------ 2 2
$$- 3 \cdot \sqrt[3]{2} - 3 \log{\left(2 \right)} + \frac{3}{2} + \frac{3 \cdot 2^{\frac{2}{3}}}{2} + 3 \log{\left(1 + \sqrt[3]{2} \right)}$$
The graph
Use the examples entering the upper and lower limits of integration.