Integral of x^3-3x^2+1 dx
The solution
Detail solution
-
Integrate term-by-term:
-
The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
-
The integral of a constant times a function is the constant times the integral of the function:
∫(−3x2)dx=−∫3x2dx
-
The integral of a constant times a function is the constant times the integral of the function:
∫3x2dx=3∫x2dx
-
The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: x3
So, the result is: −x3
-
The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 4x4−x3+x
-
Add the constant of integration:
4x4−x3+x+constant
The answer is:
4x4−x3+x+constant
The answer (Indefinite)
[src]
/
| 4
| / 3 2 \ 3 x
| \x - 3*x + 1/ dx = C + x - x + --
| 4
/
4x4−x3+x
The graph
Use the examples entering the upper and lower limits of integration.