Integral of (x^3)/(4-x^2) dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Let u=x2.
Then let du=2xdx and substitute −du:
∫(−2u−8u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫2u−8udu=−∫2u−8udu
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Rewrite the integrand:
2u−8u=21+u−42
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫21du=2u
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The integral of a constant times a function is the constant times the integral of the function:
∫u−42du=2∫u−41du
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Let u=u−4.
Then let du=du and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(u−4)
So, the result is: 2log(u−4)
The result is: 2u+2log(u−4)
So, the result is: −2u−2log(u−4)
Now substitute u back in:
−2x2−2log(x2−4)
Method #2
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Rewrite the integrand:
4−x2x3=−x−x+22−x−22
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x)dx=−∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x+22)dx=−2∫x+21dx
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Let u=x+2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x+2)
So, the result is: −2log(x+2)
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x−22)dx=−2∫x−21dx
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Let u=x−2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
So, the result is: −2log(x−2)
The result is: −2x2−2log(x−2)−2log(x+2)
Method #3
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Rewrite the integrand:
4−x2x3=−x2−4x3
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x2−4x3)dx=−∫x2−4x3dx
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Let u=x2.
Then let du=2xdx and substitute du:
∫2u−8udu
-
Rewrite the integrand:
2u−8u=21+u−42
-
Integrate term-by-term:
-
The integral of a constant is the constant times the variable of integration:
∫21du=2u
-
The integral of a constant times a function is the constant times the integral of the function:
∫u−42du=2∫u−41du
-
Let u=u−4.
Then let du=du and substitute du:
∫u1du
-
The integral of u1 is log(u).
Now substitute u back in:
log(u−4)
So, the result is: 2log(u−4)
The result is: 2u+2log(u−4)
Now substitute u back in:
2x2+2log(x2−4)
So, the result is: −2x2−2log(x2−4)
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Add the constant of integration:
−2x2−2log(x2−4)+constant
The answer is:
−2x2−2log(x2−4)+constant
The answer (Indefinite)
[src]
/
|
| 3 2
| x / 2\ x
| ------ dx = C - 2*log\-4 + x / - --
| 2 2
| 4 - x
|
/
∫4−x2x3dx=C−2x2−2log(x2−4)
The graph
-1/2 - 2*log(3) + 2*log(4)
−2log(3)−21+2log(4)
=
-1/2 - 2*log(3) + 2*log(4)
−2log(3)−21+2log(4)
-1/2 - 2*log(3) + 2*log(4)
Use the examples entering the upper and lower limits of integration.