Integral of x^4cosx dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=x4 and let dv(x)=cos(x).
Then du(x)=4x3.
To find v(x):
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The integral of cosine is sine:
∫cos(x)dx=sin(x)
Now evaluate the sub-integral.
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=4x3 and let dv(x)=sin(x).
Then du(x)=12x2.
To find v(x):
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The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
Now evaluate the sub-integral.
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=−12x2 and let dv(x)=cos(x).
Then du(x)=−24x.
To find v(x):
-
The integral of cosine is sine:
∫cos(x)dx=sin(x)
Now evaluate the sub-integral.
-
Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=−24x and let dv(x)=sin(x).
Then du(x)=−24.
To find v(x):
-
The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
Now evaluate the sub-integral.
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The integral of a constant times a function is the constant times the integral of the function:
∫24cos(x)dx=24∫cos(x)dx
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The integral of cosine is sine:
∫cos(x)dx=sin(x)
So, the result is: 24sin(x)
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Add the constant of integration:
x4sin(x)+4x3cos(x)−12x2sin(x)−24xcos(x)+24sin(x)+constant
The answer is:
x4sin(x)+4x3cos(x)−12x2sin(x)−24xcos(x)+24sin(x)+constant
The answer (Indefinite)
[src]
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| 4 4 2 3
| x *cos(x) dx = C + 24*sin(x) + x *sin(x) - 24*x*cos(x) - 12*x *sin(x) + 4*x *cos(x)
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∫x4cos(x)dx=C+x4sin(x)+4x3cos(x)−12x2sin(x)−24xcos(x)+24sin(x)
The graph
−20cos(1)+13sin(1)
=
−20cos(1)+13sin(1)
Use the examples entering the upper and lower limits of integration.