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Integral of x+2/(x+3)^3 dx

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The solution

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 |  /       2    \   
 |  |x + --------| dx
 |  |           3|   
 |  \    (x + 3) /   
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00(x+2(x+3)3)dx\int\limits_{0}^{0} \left(x + \frac{2}{\left(x + 3\right)^{3}}\right)\, dx
Integral(x + 2/(x + 3)^3, (x, 0, 0))
Detail solution
  1. Integrate term-by-term:

    1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

      xdx=x22\int x\, dx = \frac{x^{2}}{2}

    1. The integral of a constant times a function is the constant times the integral of the function:

      2(x+3)3dx=21(x+3)3dx\int \frac{2}{\left(x + 3\right)^{3}}\, dx = 2 \int \frac{1}{\left(x + 3\right)^{3}}\, dx

      1. Don't know the steps in finding this integral.

        But the integral is

        12x2+12x+18- \frac{1}{2 x^{2} + 12 x + 18}

      So, the result is: 22x2+12x+18- \frac{2}{2 x^{2} + 12 x + 18}

    The result is: x2222x2+12x+18\frac{x^{2}}{2} - \frac{2}{2 x^{2} + 12 x + 18}

  2. Now simplify:

    x2(x2+6x+9)22(x2+6x+9)\frac{x^{2} \left(x^{2} + 6 x + 9\right) - 2}{2 \left(x^{2} + 6 x + 9\right)}

  3. Add the constant of integration:

    x2(x2+6x+9)22(x2+6x+9)+constant\frac{x^{2} \left(x^{2} + 6 x + 9\right) - 2}{2 \left(x^{2} + 6 x + 9\right)}+ \mathrm{constant}


The answer is:

x2(x2+6x+9)22(x2+6x+9)+constant\frac{x^{2} \left(x^{2} + 6 x + 9\right) - 2}{2 \left(x^{2} + 6 x + 9\right)}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                                             
 |                          2                   
 | /       2    \          x           2        
 | |x + --------| dx = C + -- - ----------------
 | |           3|          2            2       
 | \    (x + 3) /               18 + 2*x  + 12*x
 |                                              
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(x+2(x+3)3)dx=C+x2222x2+12x+18\int \left(x + \frac{2}{\left(x + 3\right)^{3}}\right)\, dx = C + \frac{x^{2}}{2} - \frac{2}{2 x^{2} + 12 x + 18}
The graph
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The answer [src]
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Numerical answer [src]
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    Use the examples entering the upper and lower limits of integration.