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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of x^4lnx
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Integral of dx/sinxcosx
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Integral of (2x+3)
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Integral of 1/(1-cos(x))
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Identical expressions
- (x+ four)/(two x^2-7x+ one)
- (x plus 4) divide by (2x squared minus 7x plus 1)
- (x plus four) divide by (two x squared minus 7x plus one)
- (x+4)/(2x2-7x+1)
- x+4/2x2-7x+1
- (x+4)/(2x²-7x+1)
- (x+4)/(2x to the power of 2-7x+1)
- x+4/2x^2-7x+1
- (x+4) divide by (2x^2-7x+1)
- (x+4)/(2x^2-7x+1)dx
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Similar expressions
- (x+4)/(2x^2-7x-1)
- (x+4)/(2x^2+7x+1)
- (x-4)/(2x^2-7x+1)
Integral of (x+4)/(2x^2-7x+1) dx
The solution
You have entered
[src]
1 / | | x + 4 | -------------- dx | 2 | 2*x - 7*x + 1 | / 0
$$\int\limits_{0}^{1} \frac{x + 4}{2 x^{2} - 7 x + 1}\, dx$$
Integral((x + 4)/(2*x^2 - 7*x + 1), (x, 0, 1))
The answer (Indefinite)
[src]
/ / ____\ / ____\\ / ____ | | 7 \/ 41 | | 7 \/ 41 || | / 2\ 23*\/ 41 *|- log|- - + x + ------| + log|- - + x - ------|| | x + 4 log\1 - 7*x + 2*x / \ \ 4 4 / \ 4 4 // | -------------- dx = C + ------------------- + ----------------------------------------------------------- | 2 4 164 | 2*x - 7*x + 1 | /
$${{23\,\log \left({{4\,x-\sqrt{41}-7}\over{4\,x+\sqrt{41}-7}}\right)
}\over{4\,\sqrt{41}}}+{{\log \left(2\,x^2-7\,x+1\right)}\over{4}}$$
The graph
The answer
[src]
nan
$$-{{23\,\log \left({{630\,\sqrt{41}}\over{14147\,\sqrt{41}-90585}}-
{{4034}\over{14147\,\sqrt{41}-90585}}\right)}\over{4\,\sqrt{41}}}+{{
23\,\log \left({{600\,\sqrt{41}}\over{1683\,\sqrt{41}-10825}}-{{3976
}\over{1683\,\sqrt{41}-10825}}\right)}\over{4\,\sqrt{41}}}+{{\log 4
}\over{4}}$$
=
=
nan
$$\text{NaN}$$
The graph
Use the examples entering the upper and lower limits of integration.