Integral of x/2+1 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫2xdx=2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 4x2
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 4x2+x
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Now simplify:
4x(x+4)
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Add the constant of integration:
4x(x+4)+constant
The answer is:
4x(x+4)+constant
The answer (Indefinite)
[src]
/
| 2
| /x \ x
| |- + 1| dx = C + x + --
| \2 / 4
|
/
∫(2x+1)dx=C+4x2+x
The graph
4π2+π
=
4π2+π
Use the examples entering the upper and lower limits of integration.