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- Improper integral
- Double Integral
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- Curvilinear integral
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How to use it?
- Integral of d{x}:
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Integral of 1/(x+2)^2
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Integral of xarctanx
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Integral of e^(x^3)
- Integral of ln(x)/x^3
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Identical expressions
- x/sqrt(5x^ two -2x+ one)
- x divide by square root of (5x squared minus 2x plus 1)
- x divide by square root of (5x to the power of two minus 2x plus one)
- x/√(5x^2-2x+1)
- x/sqrt(5x2-2x+1)
- x/sqrt5x2-2x+1
- x/sqrt(5x²-2x+1)
- x/sqrt(5x to the power of 2-2x+1)
- x/sqrt5x^2-2x+1
- x divide by sqrt(5x^2-2x+1)
- x/sqrt(5x^2-2x+1)dx
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Similar expressions
- x/sqrt(5x^2+2x+1)
- x*dx/sqrt(5*x^2-2*x+1)
- x/sqrt(5x^2-2x-1)
Integral of x/sqrt(5x^2-2x+1) dx
The solution
You have entered
[src]
1 / | | x | ------------------- dx | ________________ | / 2 | \/ 5*x - 2*x + 1 | / 0
$$\int\limits_{0}^{1} \frac{x}{\sqrt{\left(5 x^{2} - 2 x\right) + 1}}\, dx$$
Integral(x/sqrt(5*x^2 - 2*x + 1), (x, 0, 1))
The answer (Indefinite)
[src]
/ / | | | x | x | ------------------- dx = C + | ------------------- dx | ________________ | ________________ | / 2 | / 2 | \/ 5*x - 2*x + 1 | \/ 1 - 2*x + 5*x | | / /
$$\int \frac{x}{\sqrt{\left(5 x^{2} - 2 x\right) + 1}}\, dx = C + \int \frac{x}{\sqrt{5 x^{2} - 2 x + 1}}\, dx$$
The answer
[src]
1 / | | x | ------------------- dx | ________________ | / 2 | \/ 1 - 2*x + 5*x | / 0
$$\int\limits_{0}^{1} \frac{x}{\sqrt{5 x^{2} - 2 x + 1}}\, dx$$
=
=
1 / | | x | ------------------- dx | ________________ | / 2 | \/ 1 - 2*x + 5*x | / 0
$$\int\limits_{0}^{1} \frac{x}{\sqrt{5 x^{2} - 2 x + 1}}\, dx$$
Integral(x/sqrt(1 - 2*x + 5*x^2), (x, 0, 1))
Use the examples entering the upper and lower limits of integration.