Integral of 2x^2-x+1 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫2x2dx=2∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: 32x3
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x)dx=−∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
The result is: 32x3−2x2
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 32x3−2x2+x
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Now simplify:
6x(4x2−3x+6)
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Add the constant of integration:
6x(4x2−3x+6)+constant
The answer is:
6x(4x2−3x+6)+constant
The answer (Indefinite)
[src]
/
| 2 3
| / 2 \ x 2*x
| \2*x - x + 1/ dx = C + x - -- + ----
| 2 3
/
∫((2x2−x)+1)dx=C+32x3−2x2+x
The graph
Use the examples entering the upper and lower limits of integration.