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- Improper integral
- Double Integral
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How to use it?
- Integral of d{x}:
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Integral of exp(x)/x
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Integral of x*exp(-x^2)
- Integral of x/(x-1)^2
- Integral of lnx^2
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Identical expressions
- (two x- one)/(2x^2+8x- six)
- (2x minus 1) divide by (2x squared plus 8x minus 6)
- (two x minus one) divide by (2x squared plus 8x minus six)
- (2x-1)/(2x2+8x-6)
- 2x-1/2x2+8x-6
- (2x-1)/(2x²+8x-6)
- (2x-1)/(2x to the power of 2+8x-6)
- 2x-1/2x^2+8x-6
- (2x-1) divide by (2x^2+8x-6)
- (2x-1)/(2x^2+8x-6)dx
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Similar expressions
- (2x-1)/(2x^2+8x+6)
- (2x+1)/(2x^2+8x-6)
- (2x-1)/(2x^2-8x-6)
- 2x-1/2x^2+8x-6
Integral of (2x-1)/(2x^2+8x-6) dx
The solution
You have entered
[src]
1 / | | 2*x - 1 | -------------- dx | 2 | 2*x + 8*x - 6 | / 0
$$\int\limits_{0}^{1} \frac{2 x - 1}{2 x^{2} + 8 x - 6}\, dx$$
Integral((2*x - 1*1)/(2*x^2 + 8*x - 1*6), (x, 0, 1))
The answer (Indefinite)
[src]
/ | / 2 \ ___ / / ___\ / ___ \\ | 2*x - 1 log\-12 + 4*x + 16*x/ 5*\/ 7 *\- log\4 + 2*x + 2*\/ 7 / + log\4 - 2*\/ 7 + 2*x// | -------------- dx = C + ---------------------- - ----------------------------------------------------------- | 2 2 28 | 2*x + 8*x - 6 | /
$${{\log \left(x^2+4\,x-3\right)}\over{2}}-{{5\,\log \left({{2\,x-2\,
\sqrt{7}+4}\over{2\,x+2\,\sqrt{7}+4}}\right)}\over{4\,\sqrt{7}}}$$
The graph
The answer
[src]
nan
$${{5\,\log \left({{3}\over{4\,\sqrt{7}+11}}\right)}\over{4\,\sqrt{7}
}}+{{5\,\log \left(3\,\sqrt{7}+8\right)}\over{4\,\sqrt{7}}}-{{\log 3
}\over{2}}+{{\log 2}\over{2}}$$
=
=
nan
$$\text{NaN}$$
The graph
Use the examples entering the upper and lower limits of integration.