Integral of 2^x/ln(x) dx
The solution
The answer (Indefinite)
[src]
/ /
| |
| x | x
| 2 | 2
| ------ dx = C + | ------ dx
| log(x) | log(x)
| |
/ /
∫log(x)2xdx=C+∫log(x)2xdx
1
/
|
| x
| 2
| ------ dx
| log(x)
|
/
0
0∫1log(x)2xdx
=
1
/
|
| x
| 2
| ------ dx
| log(x)
|
/
0
0∫1log(x)2xdx
Integral(2^x/log(x), (x, 0, 1))
Use the examples entering the upper and lower limits of integration.