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(two -sinx)/(2x+cosx)
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(two minus sinus of x) divide by (2x plus co sinus of e of x)
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(2-sinx) divide by (2x+cosx)
(2-sinx)/(2x+cosx)dx
Similar expressions
(2-sinx)/(2x-cosx)
(2+sinx)/(2x+cosx)

Integral of (2-sinx)/(2x+cosx) dx

The solution

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  1                
  /                
 |                 
 |   2 - sin(x)    
 |  ------------ dx
 |  2*x + cos(x)   
 |                 
/                  
0

$$\int\limits_{0}^{1} \frac{2 - \sin{\left(x \right)}}{2 x + \cos{\left(x \right)}}\, dx$$

Integral((2 - sin(x))/(2*x + cos(x)), (x, 0, 1))

Detail solution

There are multiple ways to do this integral.
Method #1
1. Let $u = 2 x + \cos{\left(x \right)}$ .
  
  Then let $du = \left(2 - \sin{\left(x \right)}\right) dx$ and substitute $du$ :
  
  $\int \frac{1}{u}\, du$
  1. The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
  Now substitute $u$ back in:
  
  $\log{\left(2 x + \cos{\left(x \right)} \right)}$
Method #2
1. Rewrite the integrand:
  
  $\frac{2 - \sin{\left(x \right)}}{2 x + \cos{\left(x \right)}} = - \frac{\sin{\left(x \right)} - 2}{2 x + \cos{\left(x \right)}}$
2. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int \left(- \frac{\sin{\left(x \right)} - 2}{2 x + \cos{\left(x \right)}}\right)\, dx = - \int \frac{\sin{\left(x \right)} - 2}{2 x + \cos{\left(x \right)}}\, dx$
  1. Let $u = 2 x + \cos{\left(x \right)}$ .
    
    Then let $du = \left(2 - \sin{\left(x \right)}\right) dx$ and substitute $- du$ :
    
    $\int \left(- \frac{1}{u}\right)\, du$
    1. The integral of a constant times a function is the constant times the integral of the function:
      
      $\int \frac{1}{u}\, du = - \int \frac{1}{u}\, du$
      
      The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
      
      So, the result is: $- \log{\left(u \right)}$
    Now substitute $u$ back in:
    
    $- \log{\left(2 x + \cos{\left(x \right)} \right)}$
  So, the result is: $\log{\left(2 x + \cos{\left(x \right)} \right)}$
Add the constant of integration:

$\log{\left(2 x + \cos{\left(x \right)} \right)}+ \mathrm{constant}$

The answer is:

$\log{\left(2 x + \cos{\left(x \right)} \right)}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                       
 |                                        
 |  2 - sin(x)                            
 | ------------ dx = C + log(2*x + cos(x))
 | 2*x + cos(x)                           
 |                                        
/

$$\int \frac{2 - \sin{\left(x \right)}}{2 x + \cos{\left(x \right)}}\, dx = C + \log{\left(2 x + \cos{\left(x \right)} \right)}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

log(2 + cos(1))

$$\log{\left(\cos{\left(1 \right)} + 2 \right)}$$

log(2 + cos(1))

$$\log{\left(\cos{\left(1 \right)} + 2 \right)}$$

log(2 + cos(1))

Numerical answer [src]

0.932283092006681

0.932283092006681

Use the examples entering the upper and lower limits of integration.

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How to use it?

Identical expressions

Similar expressions

Integral of (2-sinx)/(2x+cosx) dx

Limits of integration:

The graph:

Piecewise:

The solution

Method #1

Method #2