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Solving integrals/ 2(cos^2)*sinz

Integral of 2(cos^2)*sinz dz

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src] 
 pi                    
  /                    
 |                     
 |       2             
 |  2*cos (x)*sin(z) dz
 |                     
/                      
0
$$\int\limits_{0}^{\pi} \sin{\left(z \right)} 2 \cos^{2}{\left(x \right)}\, dz$$ 
Integral((2*cos(x)^2)*sin(z), (z, 0, pi))
Detail solution

  1. The integral of a constant times a function is the constant times the integral of the function:

    1. The integral of sine is negative cosine:

    So, the result is:

  2. Add the constant of integration:

The answer is:

The answer (Indefinite) [src] 
  /                                          
 |                                           
 |      2                         2          
 | 2*cos (x)*sin(z) dz = C - 2*cos (x)*cos(z)
 |                                           
/
$$\int \sin{\left(z \right)} 2 \cos^{2}{\left(x \right)}\, dz = C - 2 \cos^{2}{\left(x \right)} \cos{\left(z \right)}$$
Simplify
The answer [src] 
     2   
4*cos (x)
$$4 \cos^{2}{\left(x \right)}$$ 
=
= 
     2   
4*cos (x)
$$4 \cos^{2}{\left(x \right)}$$ 
4*cos(x)^2

    Use the examples entering the upper and lower limits of integration.

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