Integral of (3x^2)*(e^-x^3) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫3x2e−x3dx=3∫x2e−x3dx
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Let u=e−x3.
Then let du=−3x2e−x3dx and substitute −3du:
∫91du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−31)du=−3∫1du
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: −3u
Now substitute u back in:
−3e−x3
So, the result is: −e−x3
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Add the constant of integration:
−e−x3+constant
The answer is:
−e−x3+constant
The answer (Indefinite)
[src]
/
|
| 3 3
| 2 -x -x
| 3*x *e dx = C - e
|
/
The graph
3(3e−8−3e−oo3)
=
Use the examples entering the upper and lower limits of integration.