Integral of 3^(2*x) dx
The solution
Detail solution
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Let u=2x.
Then let du=2dx and substitute 2du:
∫23udu
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The integral of a constant times a function is the constant times the integral of the function:
∫3udu=2∫3udu
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The integral of an exponential function is itself divided by the natural logarithm of the base.
∫3udu=log(3)3u
So, the result is: 2log(3)3u
Now substitute u back in:
2log(3)32x
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Now simplify:
2log(3)9x
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Add the constant of integration:
2log(3)9x+constant
The answer is:
2log(3)9x+constant
The answer (Indefinite)
[src]
/
| 2*x
| 2*x 3
| 3 dx = C + --------
| 2*log(3)
/
∫32xdx=2log(3)32x+C
The graph
log(3)4
=
log(3)4
Use the examples entering the upper and lower limits of integration.