Integral of 3*x³+4x dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫3x3dx=3∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: 43x4
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The integral of a constant times a function is the constant times the integral of the function:
∫4xdx=4∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 2x2
The result is: 43x4+2x2
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Now simplify:
4x2(3x2+8)
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Add the constant of integration:
4x2(3x2+8)+constant
The answer is:
4x2(3x2+8)+constant
The answer (Indefinite)
[src]
/
| 4
| / 3 \ 2 3*x
| \3*x + 4*x/ dx = C + 2*x + ----
| 4
/
∫(3x3+4x)dx=C+43x4+2x2
The graph
Use the examples entering the upper and lower limits of integration.