Integral of (7x²+3x³+4x^5) dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫4x5dx=4∫x5dx
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The integral of xn is n+1xn+1 when n=−1:
∫x5dx=6x6
So, the result is: 32x6
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫3x3dx=3∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: 43x4
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The integral of a constant times a function is the constant times the integral of the function:
∫7x2dx=7∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: 37x3
The result is: 43x4+37x3
The result is: 32x6+43x4+37x3
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Now simplify:
12x3(8x3+9x+28)
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Add the constant of integration:
12x3(8x3+9x+28)+constant
The answer is:
12x3(8x3+9x+28)+constant
The answer (Indefinite)
[src]
/
| 6 4 3
| / 2 3 5\ 2*x 3*x 7*x
| \7*x + 3*x + 4*x / dx = C + ---- + ---- + ----
| 3 4 3
/
∫(4x5+(3x3+7x2))dx=C+32x6+43x4+37x3
The graph
Use the examples entering the upper and lower limits of integration.