Integral of (3/x)-2*sin(5*x)+1 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−2sin(5x))dx=−2∫sin(5x)dx
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Let u=5x.
Then let du=5dx and substitute 5du:
∫5sin(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫sin(u)du=5∫sin(u)du
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The integral of sine is negative cosine:
∫sin(u)du=−cos(u)
So, the result is: −5cos(u)
Now substitute u back in:
−5cos(5x)
So, the result is: 52cos(5x)
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The integral of a constant times a function is the constant times the integral of the function:
∫x3dx=3∫x1dx
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The integral of x1 is log(x).
So, the result is: 3log(x)
The result is: 3log(x)+52cos(5x)
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: x+3log(x)+52cos(5x)
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Add the constant of integration:
x+3log(x)+52cos(5x)+constant
The answer is:
x+3log(x)+52cos(5x)+constant
The answer (Indefinite)
[src]
/
|
| /3 \ 2*cos(5*x)
| |- - 2*sin(5*x) + 1| dx = C + x + 3*log(x) + ----------
| \x / 5
|
/
∫((−2sin(5x)+x3)+1)dx=C+x+3log(x)+52cos(5x)
The graph
Use the examples entering the upper and lower limits of integration.