Integral of tan^2(x/2) dx
The solution
Detail solution
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Rewrite the integrand:
tan2(2x)=sec2(2x)−1
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Integrate term-by-term:
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Don't know the steps in finding this integral.
But the integral is
cos(2x)2sin(2x)
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The integral of a constant is the constant times the variable of integration:
∫(−1)dx=−x
The result is: −x+cos(2x)2sin(2x)
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Now simplify:
−x+2tan(2x)
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Add the constant of integration:
−x+2tan(2x)+constant
The answer is:
−x+2tan(2x)+constant
The answer (Indefinite)
[src]
/ /x\
| 2*sin|-|
| 2/x\ \2/
| tan |-| dx = C - x + --------
| \2/ /x\
| cos|-|
/ \2/
∫tan2(2x)dx=C−x+cos(2x)2sin(2x)
The graph
2*sin(1/2)
-1 + ----------
cos(1/2)
−1+cos(21)2sin(21)
=
2*sin(1/2)
-1 + ----------
cos(1/2)
−1+cos(21)2sin(21)
Use the examples entering the upper and lower limits of integration.